(4^x*3^(2x))/6^(3x)^=1/36

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Solution for (4^x*3^(2x))/6^(3x)^=1/36 equation: 



(4^x*3^(2x))/6^(3x)^=1/36

We move all terms to the left:

(4^x*3^(2x))/6^(3x)^-(1/36)=0



Domain of the equation: 6^3x^!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(4^x*3^2x)/6^3x^-(+1/36)=0

We get rid of parentheses

(4^x*3^2x)/6^3x^-1/36=0

We calculate fractions

We do not support expression: x^3

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